250=x^2+5x+50

Solution for 250=x^2+5x+50 equation:

250=x^2+5x+50

We move all terms to the left:

250-(x^2+5x+50)=0

We get rid of parentheses

-x^2-5x-50+250=0

We add all the numbers together, and all the variables

-1x^2-5x+200=0

a = -1; b = -5; c = +200;
Δ = b2-4ac
Δ = -52-4·(-1)·200
Δ = 825
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{825}=\sqrt{25*33}=\sqrt{25}*\sqrt{33}=5\sqrt{33}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5\sqrt{33}}{2*-1}=\frac{5-5\sqrt{33}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5\sqrt{33}}{2*-1}=\frac{5+5\sqrt{33}}{-2}
$